4p^2-13p+9=0

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Solution for 4p^2-13p+9=0 equation: 



4p^2-13p+9=0

a = 4; b = -13; c = +9;
Δ = b2-4ac
Δ = -132-4·4·9
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$


$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-5}{2*4}=\frac{8}{8}
=1
$


$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+5}{2*4}=\frac{18}{8}
=2+1/4
$

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